byplcy's recent timeline updates
byplcy

byplcy

V2EX member #273132, joined on 2017-12-08 00:38:19 +08:00
Today's activity rank 8711
byplcy's recent replies
8h 41m ago
Replied to a topic by yomige 程序员 anytls 协议有什么过人之处?
别钓鱼了
done !
Mar 20
Replied to a topic by aicodingsh 推广 领$10-稳定 - Claude Code 用户看过来
vpOD7z 谢谢大佬
来自站点:Terminal.Pub ,我的 id 是:4425
请教个问题,
make 后输入手机号 格式为 +8613800138000
我确认 电报 api_id/api_hash 都是对的
会显示这个错误:
Traceback (most recent call last):
File "pull.py", line 222, in <module>
client = ChannelTelegramClient(SESSION, API_ID, API_HASH)
File "pull.py", line 152, in __init__
self.sign_in(user_phone)
File "/usr/local/lib/python3.6/site-packages/telethon/sync.py", line 39, in syncified
return loop.run_until_complete(coro)
File "/usr/lib64/python3.6/asyncio/base_events.py", line 484, in run_until_complete
return future.result()
File "/usr/local/lib/python3.6/site-packages/telethon/client/auth.py", line 319, in sign_in
return await self.send_code_request(phone)
File "/usr/local/lib/python3.6/site-packages/telethon/client/auth.py", line 474, in send_code_request
phone, self.api_id, self.api_hash, types.CodeSettings()))
File "/usr/local/lib/python3.6/site-packages/telethon/client/users.py", line 64, in __call__
result = await future
telethon.errors.rpcerrorlist.ApiIdInvalidError: The api_id/api_hash combination is invalid (caused by SendCodeRequest)
make: *** [Makefile:11: pull] Error 1
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