飞猪

@powtop 如题

晕,请无视.

from pprint import pprint
pprint(data)

# Python
def sqrt(num, deli):
val_min = num - deli
val_max = num + deli
point = 1
while 1:
lower, bigger = [point, num] if num > point else [num, point]
mid = (lower + bigger)/2
tmp = mid ** 2
if tmp < val_min:
point, num = mid, bigger
num = bigger
elif tmp > val_max:
point, num = lower, mid
elif val_min < tmp < val_max:
return mid

print(sqrt(16, 0.21)) # 3.98828125

给楼主点自信...http://dick129418-3-dick129418.hz.tenxapp.com/

a_list = [{'100024': 100}, {'102234': 996}]
b_list = [{'100024': 200}, {'102234': 996}]

a_dict = dict((k, dic[k]) for dic in a_list for k in dic)
b_dict = dict((k, dic[k]) for dic in b_list for k in dic)

common = dict((k, (a_dict[k], b_dict[k])) for k in a_dict if k in b_dict)

print(common) # = {'100024': (100, 200), '102234': (996, 996)}

很简单,把列表转换成单个字典就行了
然后直接比较

才入手 miix5 7100...

为啥感觉招的偏前段呢...我比较重后端呢,后端一条龙路过..

http://dicka-2-dick129418.hz.tenxapp.com/ (tornado, sqllite, redis)

魔力世纪

inst

6 得很,哪里来的资源哦

'''
def login_check(func):
def _login_check(req):
try:
_ = req.session['name']
if not _:
return HttpResponseRedirect('/blog/login')
except:
return HttpResponseRedirect('/blog/login')
else:
return func(req)
return _login_check
'''

不错不错,网站别挂哈

多给宝贵意见,谢谢.说不定到时候大家还能用上~