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dhb233
V2EX  ›  程序员

邮件的收件人在源码里不需要指定吗?

  •  
  •   dhb233 · May 24, 2024 · 1760 views
    This topic created in 737 days ago, the information mentioned may be changed or developed.

    这个帖子 t/1043592 我也收到了类似的邮件,比较奇怪的是收件人。 收到的是 139 邮箱。但是收件人是手机号 @163.com,印象中没注册过 163 邮箱,尝试登陆,也提示冻结。 所以收件人为什么是错误的?

    收件人图

    源码

    X-RM-TagInfo: emlType=0                                       
    X-RM-SPAM:                                                                                        
    X-RM-SPAM-FLAG:00000000
    Received:from  (unknown[207.226.244.122])
        by rmmx-lg_mx16-12075 (RichMail) with SMTP id 2f2b665032ee627-ab6f1;
        Fri, 24 May 2024 14:25:51 +0800 (CST)
    X-RM-TRANSID:2f2b665032ee627-ab6f1
    X-CSE-ConnectionGUID: HsSPZU5hSWuPz5NK+NaouQ==
    X-CSE-MsgGUID: GrB1DL6mQtG5oQjyGFB8HA==
    X-IronPort-AV: E=Sophos;i="6.08,184,1712592000"; 
       d="scan'208";a="2759498"
    Date: Fri, 24 May 2024 14:25:39 +0800 (CST)
    From: [email protected]
    Message-ID: <[email protected]>
    Subject: =?UTF-8?B?6YKu5Lu26YCa55+l5rWL6K+V77yI5b+955Wl77yJ?=
    MIME-Version: 1.0
    Content-Type: multipart/mixed; 
        boundary="----=_Part_647478_1586142583.1716531939402"
    guardmail: guardmail
    
    ------=_Part_647478_1586142583.1716531939402
    Content-Type: multipart/alternative; 
        boundary="----=_Part_647479_1048945230.1716531939402"
    
    ------=_Part_647479_1048945230.1716531939402
    Content-Type: text/html;charset=utf-8
    Content-Transfer-Encoding: base64
    
    PHA+6YKu5Lu26YCa55+l5rWL6K+VPC9wPg==
    ------=_Part_647479_1048945230.1716531939402--
    
    ------=_Part_647478_1586142583.1716531939402--
    
    2 replies    2024-05-24 16:18:19 +08:00
    dhb233
        1
    dhb233  
    OP
       May 24, 2024
    为什么图片加载不出来。。。
    ![img]( https://imgur.com/a/W9LTZxT)
    hefish
        2
    hefish  
       May 24, 2024
    这个邮件正文了吧,具体收件人还是 smtp 协议的指定的收件人。不在正文里。
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